find hcf of 1860 and 2015 using euclid division form lemma
Answers
Answered by
210
Hi,
Euclid's division lemma:
Given positive numbers a and b ,
there exist whole numbers q and r
satisfying ,
a = bq + r ,
0 ≤ r < b
Applying Euclid's division lemma to
2015 and 1860, we get
2015 = 1860 × 1 + 155
1860 = 155 × 12 + 0
Notice that the remainder has
become zero,
and we claim that the HCF of 1860,
and 2015 is divisor at this stage is ,
i.e 155.
HCF(1860,2015) = 155
I hope this helps you.
:)
Euclid's division lemma:
Given positive numbers a and b ,
there exist whole numbers q and r
satisfying ,
a = bq + r ,
0 ≤ r < b
Applying Euclid's division lemma to
2015 and 1860, we get
2015 = 1860 × 1 + 155
1860 = 155 × 12 + 0
Notice that the remainder has
become zero,
and we claim that the HCF of 1860,
and 2015 is divisor at this stage is ,
i.e 155.
HCF(1860,2015) = 155
I hope this helps you.
:)
Answered by
50
Answer:
155
Step-by-step explanation:
Given numbers,
1860 and 2015
By using prime factorization method
1860=2×2×5×3×31
2015=5×13×31
HCF = 5×31
= 155
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