Math, asked by mamidihasini8, 1 month ago

find HCF of 20,24,28 in prime factorisation method​

Answers

Answered by technicalmokib
0

Answer:

Problem & Workout :

step 1 Address input parameters & values.

Integers: 20 24 28

lcm (20, 24, 28) = ?

step 2 Arrange the group of numbers in the horizontal form with space or comma separated format

20, 24 and 28

step 3 Choose the divisor which divides each or most of the integers of in the group (20, 24 and 28), divide each integers separately and write down the quotient in the next line right under the respective integers. Bring down the integer to the next line if the integer is not divisible by the divisor. Repeat the same process until all the integers are brought to 1.

LCM of 20, 24 and 28

4 20 24 28

5 5 6 7

6 1 6 7

7 1 1 7

1 1 1

step 4 Multiply the divisors to find the lcm of 20, 24 and 28

4 x 5 x 6 x 7 = 840

LCM(20, 24, 28) = 840

The least common multiple for three numbers 20, 24 and 28 is 840

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