Find HCF of 28 and 48 using Euclid Game method .
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Answer:
since, 48> 28
Then apply Euclid's division lemma on 48 and 28, we get
48= 28×1+20
since, remainder is not 0,then again apply Euclid's division lemma on 28 and 20, we get
28= 20×1+8
since, remainder is not 0, then again apply Euclid's division lemma on 20 and 8, we get
20= 8×2+4
since remainder is not 0, then again apply Euclid's division lemma on 8 and 4, we get
8= 4×2+0
since remainder is 0
Therefore 4 is the H.C.F of 48 and 28.
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