Question

Find HCF of 3(x^4 - x^2y^2), 6xy(x^2 - y^2),96(x^3y + y^4)

Answer 1

Answer:

Factorisation of numbers :

$3( {x}^{4} - {x}^{2} {y}^{2} ) = 3 {x}^{2} ( {x}^{2} - {y}^{2} ) \\ 6xy( {x}^{2} - {y}^{2} ) = 6xy( {x}^{2} - {y}^{2} ) \\ 96( {x}^{3} y + {y}^{4} ) = 96y( {x}^{3} + {y}^{3} )$

HCF = 3