Question

find hcf of 4052 and 12576 and show on form of 4052x +12576yfind the value of x and y

Answer 1

The factors of 4052 are: 1, 2, 4, 1013, 2026, 4052

The factors of 12576 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96, 131, 262, 393, 524, 786, 1048, 1572, 2096, 3144, 4192, 6288, 12576

Then the highest common factor is 4.

4052x +12576y = 4
4052 * (1/2026) +12576 * (1/6288) = 4

x = 1/2026
y = 1/6288

Answer 2

Answer:

Step-by-step explanation:

The value of H+A+B is 349

Step-by-step explanation:

Given if h is the HCF of 4052 and 12576 and h=4052×A+ 12576 × B then

we have to find the value of h + A + B

 

So HCF = H = 4

 

 

 

 

 

 

 

 

 

 

Comparing with H = 4052a + 12576b, we get

H=4, A=509 and B= -164