find HCF of 445and 42 using Euclid division lemma
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Euclid division lemma :-
a = bq + r
0 ≤ r < b
a > b
(i)445 and 42
445 = 42 × 10 + 35
42 = 35 × 1 + 7
35 = 7 × 5 + 0
As the remainder is equal to zero, we can not proceed further.
HCF (445,42) = 7
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