Find hcf of 45, 101, 145 by division method?
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Question:
Find hcf of 45, 101, 145 by division method?
Step-by-step explanation:
45)101(2 1)145(145
-90 -145
--------- ------------
11)45(4 0
-44 -----------
-----------
1)11(11
-11
------------
0
--------------
HCF=1
Hope it will help you :)
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