find hcf of 455 and 42 using euclids division lemma
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according to euclid division lemma
455=42*10+35
42=35*1+7
35=7*5+0
since remainder become zero at divisor 7 so 7 is hcf of 455 and 42
455=42*10+35
42=35*1+7
35=7*5+0
since remainder become zero at divisor 7 so 7 is hcf of 455 and 42
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Answer: 7
Step-by-step explanation:
We have,455>42
Using Euclid's Division Lemma/Algorithm,
455=42×10+35
Again, 42=35×1+7
Again, 35=7×5+0
Therefore, the last divisor 7 is the HCF.
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