Question

Find HCF of 52 and 117 and express it in the form 52x + 117y .
=HCF OF 52 AND 117 IS 13 , THEN HOW TO WRITE IT IN THE FORM 52X + 117Y

Answer 1

Solution:-
By Euclid's Division Lemma 117 > 52
117 = (52 × 2) + 13 (52 is the divisor)
52 = 13 × 4 + 0 ; The division process ends here, as remainder is 0. So, HCF is 13 (Here, 13 is divisor)
13 can also be expressed as 52x + 117y i.e. as 52 (-2) + 117 (1)

Answer 2

Answer:

HCF of 52 and 117 is 13

Step-by-step explanation:

2 |__ 52-------3|__ 117

2 |__ 26-------3|__ 39

13|__ 13--------13|__ 13

|__ 1----------|__ 1

52= 2×2×13. 117=3×3×13

HCF = 13