Find HCF of 65 and 117 and find a pair of integral values of m and n such that
HCF = 65m + 117n.
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1
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Therefore, divisor of last equation will be required highest common factor. Therefore, HCF of 65, 117 will be 13. Now using (1), (2) and (3) we will obtain values of m and n such that 13 = 65m + 117n.
Answered by
0
Answer:
Therefore, divisor of last equation will be required highest common factor. Therefore, HCF of 65, 117 will be 13. Now using (1), (2) and (3) we will obtain values of m and n such that 13 = 65m + 117n.
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