Find HCF of 748,408 and 512.
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748=2*2*11*17
408=2*2*2*3*17
512=2*2*2*2*2*2*2*2*2
so the common factors of 3 are 2 and 2
so H C F is 2*2=4
408=2*2*2*3*17
512=2*2*2*2*2*2*2*2*2
so the common factors of 3 are 2 and 2
so H C F is 2*2=4
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