Question

find hcf of 81 and 237 .Express the HCF in the form of 237p+81q .Find the value of
(3p +q)

answer is 1 . ​

Answer 1

Step-by-step explanation:

Given:find HCF of 81 and 237 .Express the HCF in the form of 237p+81q .

To find: Find the value of (3p +q)

Solution:

Use Euclid's Division lemma to find HCF

$237 = 81 \times 2 + 75 \\ \\ 81 = 75 \times 1 + 6 \\ \\ 75 = 6 \times 12 + 3 \\ \\ 6 = 3 \times 2 + 0$

HCF of (237,81)=3

To find value of p and q.

Take 2nd last equation

$3 = 75 - 6 \times 12 \\ \\ 3 = 75 - (81 - 75) \times 12 \\ \\ 3 = 75 +75 \times 12 - 81 \times 12 \\ \\ 3 = 75 \times 13-81 \times 12 \\ \\ 3 = (237 - 81 \times 2) \times 13 - 81 \times 12 \\ \\ 3 = 237 \times 13- 81 \times 26 -81 \times 12 \\ \\ 3 = 237 \times 13 -81 \times 38\\ \\ 3 = 237 \times 13-81 \times 38 \\ \\ 3 = 237p + 81q$

On comparison

$p = 13\\ \\ q = -38$

Find Value of 3p+q:

$3p + q \\ \\ = > 3 \times 13 -38 \\ \\ = > 39 -38 \\ \\ = > 1 \\ \\ 3p + q = 1$

Thus,

Value of 3p+q= 1

Hope it helps you.

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write the common factor and find HCF of 12, 20

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Answer 2

Answer

i hope you answered