Question

find hcf of 924,1463,1925​

Answer 1

Prime factorise 924,1463,1925 seperately.

You'll get some series of numbers:

924=______

1463=_______

1925=_______

Now write the prime factors in exponential form.

Take the prime factor with the lowest power in each one.

Now multiply those prime factors and you will get your answer.

Answer 2

Answer:

The HCF of the given data is 77.

Step-by-step explanation:

Given: The numbers are 924, 1463, and 1925​.  

We have to find the HCF of the above numbers.

• As we know that the greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

We are solving in the following way:

We have,

First, we will find the factors of the above numbers.

The factors of 924 are: $1, 2, 3, 4, 6, 7, 11, 12, 14, 21, 22, 28, 33, 42, 44, 66, 77, 84, 132, 154, 231, 308, 462, 924$

The factors of 1463 are: $1, 7, 11, 19, 77, 133, 209, 1463$

The factors of 1925 are: $1, 5, 7, 11, 25, 35, 55, 77, 175, 275, 385, 1925$

From the above, we can see that 77 is the largest positive integer that divides each of the given integers.

Then the greatest common factor(HCF) is 77.