Find hcf of 92690 , 7378 , 7161 using euclid's division lemma
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a=bq+r
a=92690. b=7378
92690=7378×13+4154
7378=4154×1+3224
4154=3224×1+930
3224=930×3+434
930=434×2+62
434=62×7+0
a=7161 b=62
7161= 62×115+31
62= 31×2+0
hcf of 92690 , 7378 , 7161 = 31
a=92690. b=7378
92690=7378×13+4154
7378=4154×1+3224
4154=3224×1+930
3224=930×3+434
930=434×2+62
434=62×7+0
a=7161 b=62
7161= 62×115+31
62= 31×2+0
hcf of 92690 , 7378 , 7161 = 31
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