find HCF of 960and432 by euclid's division method
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960
=2×480
=2×2×240
=2×2×2×120
=2×2×2×2×60
=2×2×2×2×2×30
=2×2×2×2×2×2×15
=2×2×2×2×2×2×3×5
432
=2×216
=2×2×108
=2×2×2×54
=2×2×2×2×27
=2×2×2×2×3×9
=2×2×2×2×3×3×3
therefore
HCF of 960 and 432 is
2×2×2×2×3×3×3×2×2×5
=8640
=2×480
=2×2×240
=2×2×2×120
=2×2×2×2×60
=2×2×2×2×2×30
=2×2×2×2×2×2×15
=2×2×2×2×2×2×3×5
432
=2×216
=2×2×108
=2×2×2×54
=2×2×2×2×27
=2×2×2×2×3×9
=2×2×2×2×3×3×3
therefore
HCF of 960 and 432 is
2×2×2×2×3×3×3×2×2×5
=8640
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