Math, asked by sherasinghkasel66017, 6 months ago

Find HCF of 9a² - b² and 9a²+6ab+b²​

Answers

Answered by bson
0

Step-by-step explanation:

x²-y² = (x+y)(x-y)

9a²-b² =(3a)²-b² = (3a-b)(3a+b)

9a²+6ab+b² = (3a)² + 2×3a×b +b² = (3a+b)²

x²+2xy+y² = (x+y)²

hcf = 3a+b

Answered by amitakumari93
0

Answer:

I have used the formula a^2-b^2 = (a+b)(a-b)

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