Find HCF of 9a² - b² and 9a²+6ab+b²
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Step-by-step explanation:
x²-y² = (x+y)(x-y)
9a²-b² =(3a)²-b² = (3a-b)(3a+b)
9a²+6ab+b² = (3a)² + 2×3a×b +b² = (3a+b)²
x²+2xy+y² = (x+y)²
hcf = 3a+b
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Answer:
I have used the formula a^2-b^2 = (a+b)(a-b)
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