Math, asked by vashimurugan, 9 hours ago

find HCF of a)12 , 72 b) 14, 28 and explain it ​

Answers

Answered by minakshit811
0

Answer:

Using pre factorization :-

factors of 12 =2*2*3

factors of 72=2*2*2*3*3

Hcf= 2*2*3=12

Step-by-step explanation:

as 2 ,2,3 are common in both

Answered by himanshukumar52
0

Answer:

a) HCF=12

b) HCF=14

Step-by-step explanation:

12(72)6

----72

equal 0

So HCF of 12 and 72 is the divisor that is 12.

14(28)2

----28

equal 0

So the HCF of 14 and 28 is the divisor that is 14.

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