find HCF of a)12 , 72 b) 14, 28 and explain it
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Answered by
0
Answer:
Using pre factorization :-
factors of 12 =2*2*3
factors of 72=2*2*2*3*3
Hcf= 2*2*3=12
Step-by-step explanation:
as 2 ,2,3 are common in both
Answered by
0
Answer:
a) HCF=12
b) HCF=14
Step-by-step explanation:
12(72)6
----72
equal 0
So HCF of 12 and 72 is the divisor that is 12.
14(28)2
----28
equal 0
So the HCF of 14 and 28 is the divisor that is 14.
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