Find HCF of following pairs using Euclid’s division lemma (i) 1176 and 6384 (ii) 2448 and 4284.
Answers
Answered by
9
it is right answer mark it as brainlist one
Attachments:
Answered by
3
Answer:
6384=1176×5+504
1176=504×2+168
504=168×3+0
Explanation: the remainder is zero so,the divisor is the HCF
168 is the hcf of 1176 and 6384
ii) 2448 and 4284
4284=2248×1+2036
2248=2036×1+212
2036=212×9+128
212=128×1+84
128=84×1+44
84=44×1+40
44=40×1+4
40=4×10+0
The remainder is zero then the divisor is the hcf
:)
Similar questions