Question

Find HCF of k,2k,3k,4k,5k where K is any positive integer?​

Answer 1

HCF of

k =k

2k= 2 ,k and 1

3k=3,k ans 1

4k= 2,2, k and 1

5k = 5,k and 1

k and 1 is common in all

therefore ..... k is HCF ...

Answer 2

Answer:

Nos. Are k,2k, 3k, 4k and 5k

We will first factorise them

K=k

2k=k*k

3k=k*k*k

4k=k*k*k*k

5k=k*k*k*k*k

So HCF would be the common factor that is k

Step-by-step explanation: