Question

find hcf of number 235 and 1050 using euclids division algorithm​

Answer 1

Answer:

By using EDL

a=bq+r

where a is > b

so a =867 and b=255

867=255×3+102

here r≠0 so a=255 and b=102

255=102×2+51

here r≠0 so a=102 and b=51

102=51×2+0

here r=0

so, Hcf of (867,255) is =51

Step-by-step explanation:

Answer 2

JUST WANTED TO INFORM YOU IF YOU ARE IN CBSE CLASS 9 THIS IS OUT OF SLYBUSS.