Math, asked by inception, 5 months ago

find hcf of terms and factors of (iii) 8x3y2 + 8x3
(iv) 20x3 - 40x2 + 80x
(v) x4y - 3x2y2 - 6xy3
(vi) 8x2y2 -16xy3 + 24xy​

Answers

Answered by abdullahrai4608
0

Answer:

ANSWER

(i) 12x=2×2×3×x

36=2×2×3×3

Common factor =2×3=6

(ii) 2y=2×y

22y=2×11×y

Common factor =2

(iii) 14pq=2×7×p×q

28p  

2

q  

2

=2×2×7×p×p×q×q

Common factor =14pq

(iv) 2x=2×x

3x  

2

=3×x×x

4=2×2

Common factor =1

(v) 6abc=6×a×b×c

24ab  

2

=2×2×2×3×a×b×b

12a  

2

b=2×2×3×a×a×b

Common factor =6ab

(vi) 16x  

3

=2×2×2×2×x×x×x

−4x  

2

=−2×2×x×x

32x=2×2×2×2×2×x  

Common factor =2x

(vii) 10pq=2×5×p×q

20qr=2×2×5×q×r

30rp=2×3×5

Common factor =2×5=10

(viii) 3x  

2

y  

3

=3×x×x×y×y×y

10x  

3

y  

2

=2×5×x×x×x×y×y  

6x  

2

y  

2

z=2×3×x×x×y×y×z

Common factor = x  

2

y  

2

Step-by-step explanation:

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