Math, asked by dkshaw217, 2 months ago

find HCF of the following algebraic expression: x²+xy, xz+yz,x²+ 2xy+y2​

Answers

Answered by Mahak1233
1

Answer:

Factors of x2 + xy=x(x + y)

Factors of xz + yz=z(x + y)

Factors of x2 + 2xy + y2=(x + y)2 … (from properties of (a + b)2)

GCD is the greatest common divisor, which is equal to the product of all the common divisors.

∴ the GCD of x2 + xy,xz + yz, x2 + 2xy + y2 is (x + y)

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Answered by amiro
0

Answer:

sorry it haven't HCF

please wirte correctly

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