Question

find HCF of the following numbers using euclid divison algorithm of 1024 and 90

Answer 1

Step-by-step explanation:

1024 = 90 × 11 + 34

90 = 34 × 2 + 22

34 = 22 × 1 + 12

22 = 12 × 1 + 10

12 = 10 × 1 + 2

10 = 2 × 5 + 0

So HCF = 2

Answer 2

Answer:

2

Step-by-step explanation:

1024=90×11+34

90=34×2+22

34=22×1+12

22=12×1+10

12=10×1+2

10=2×5+0

thus, H.C.F.= 2

HOPE THIS HELPS U