Find HCF of the following using Euclid's division algorithm. 1.960 and 432. 2. 870 and 225
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1)1960 and 432
using Euclid's Division Algorithm
a=bq+r
1960=432×4+232
432=232×1+200
232=200×1+32
200=32×6+8
32=8×4+0
therefore, the HCF of 1960 and 432 is 8.
2)870 and 225
using Euclid's Division Algorithm
a=bq+r
870=225×3+195
225=195×1+30
195=30×6+15
30=15×2+0
therefore, the HCF of 870 and 225 is 15
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