find hcf of the following using the prime factorization method 18,27 12, 30 15,30 32,40 12,36 20,44 14,35
Answers
Answer:
Factor of 12=2×2×3
Factor of 12=2×2×3Factor of 15=3×5
Factor of 12=2×2×3Factor of 15=3×5Factor of 21=3×7
Factor of 12=2×2×3Factor of 15=3×5Factor of 21=3×7HCF (12,15,21)=3
Factor of 12=2×2×3Factor of 15=3×5Factor of 21=3×7HCF (12,15,21)=3LCM (12,15,21)=2×2×3×5×7=420
Factor of 12=2×2×3Factor of 15=3×5Factor of 21=3×7HCF (12,15,21)=3LCM (12,15,21)=2×2×3×5×7=420(ii) 17, 23 and 29
Factor of 12=2×2×3Factor of 15=3×5Factor of 21=3×7HCF (12,15,21)=3LCM (12,15,21)=2×2×3×5×7=420(ii) 17, 23 and 29Factor of 17=1×17
Factor of 12=2×2×3Factor of 15=3×5Factor of 21=3×7HCF (12,15,21)=3LCM (12,15,21)=2×2×3×5×7=420(ii) 17, 23 and 29Factor of 17=1×17Factor of 23=1×23
Factor of 12=2×2×3Factor of 15=3×5Factor of 21=3×7HCF (12,15,21)=3LCM (12,15,21)=2×2×3×5×7=420(ii) 17, 23 and 29Factor of 17=1×17Factor of 23=1×23Factor of 29=1×29
Factor of 12=2×2×3Factor of 15=3×5Factor of 21=3×7HCF (12,15,21)=3LCM (12,15,21)=2×2×3×5×7=420(ii) 17, 23 and 29Factor of 17=1×17Factor of 23=1×23Factor of 29=1×29HCF (17,23,29)=1