Question

find HCF of two numbers whose prime factorization are expressible as 2^3×5^2×7×13 and 2^3×5×29
answer this please

Answer 1

hcf is the highest number of factors in both numbers
Here,2³*5 are the factors in both of the numbers.
thus,2³*5=40 is the hcf of these two numbers

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Answer 2

HCF of two numbers whose prime factorization are expressible as is 40

Solution:

Given that,

We have to find HCF of two numbers whose prime factorization are expressible as:

$2^3 \times 5^2 \times 7 \times 13\\\\2^3 \times 5 \times 29$

HCF is the highest number of factors that is common in both numbers

Therefore,

$\boxed { 2^3 } \times \boxed { 5 } \times 5 \times 7 \times 13\\\\ \boxed{ 2^3 } \times \boxed { 5 } \times 29$

Thus,

$HCF = 2^3 \times 5 = 8 \times 5 = 40$

Thus HCF of two numbers whose prime factorization are expressible as is 40

Learn more:

Find the H.C.F and L.C.M of two numbers whose prime factorisation is expressible in the form of as 2^3×5^2×7and2^3×3×7

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Find lcm of numbers whose prime factorisation are expressible as 3×5² and 3²×7²

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