find HCF of x cube - 3 X + 2 and x square - 4 x + 3
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Solution:
Factorizing 4x2 - 9y2, we get
(2x)2 - (3y)2, by using the identities of a2 - b2.
= (2x + 3y) (2x - 3y)
Also, factorizing 2x2 – 3xy by taking the common factor 'x', we get
= x(2x – 3y)
Therefore, H.C.F. of the polynomial 4x2 - 9y2 and 2x2 – 3xy is (2x - 3y).
http://www.math-only-math.com/highest-common-factor-of-polynomials.html
Factorizing 4x2 - 9y2, we get
(2x)2 - (3y)2, by using the identities of a2 - b2.
= (2x + 3y) (2x - 3y)
Also, factorizing 2x2 – 3xy by taking the common factor 'x', we get
= x(2x – 3y)
Therefore, H.C.F. of the polynomial 4x2 - 9y2 and 2x2 – 3xy is (2x - 3y).
http://www.math-only-math.com/highest-common-factor-of-polynomials.html
hamu7:
cube not square
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