Find HCF using ( Repeated Subtraction and Division) 56 and 12
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Let n = 56 & n = 12
m – n = 56 – 12 = 44
now,
m = 44, n = 12
m – n = 44 – 12 = 32
m – n = 32 – 12 = 20
m – n = 20 – 12 = 8
n – m = 12 – 84
m – n = 8 – 4 = 4.
now m = n
∴ HCF of 56 & 12 is 4
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