Math, asked by ssanjani094, 3 months ago


Find HCF using ( Repeated Subtraction and Division) 56 and 12​

Answers

Answered by darksoul3
16

Let n = 56 & n = 12

m – n = 56 – 12 = 44

now,

m = 44, n = 12

m – n = 44 – 12 = 32

m – n = 32 – 12 = 20

m – n = 20 – 12 = 8

n – m = 12 – 84

m – n = 8 – 4 = 4.

now m = n

∴ HCF of 56 & 12 is 4

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Answered by sam104641
1

mark my answer BRIANLIEST

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