Find hcf with edl of 4052 @nd 12576
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By euclids division lemma,
12576=4052x3+420
4052=420x9+272
420=272x1+148
272=148x1+124
148=124x1+24
124=24x5+4
24=4x6+0
Therefore HCF is 4
Hope this helps you.....
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