Question

Find HCF (x³-3x+2) and (x²-4x+3)​

Answer 1

H.C.F of (x2−3x+2) and (x2−4x+3);

Here to find the H.C.F. , we will use the method of factorisation as;

x2−3x+2 = x2−2x−x+2 = x(x−2)−1(x−2) = (x−1(x−2)

x2−4x+3= x2−3x−x+3 = x(x−3)−1(x−3) = (x−1)(x−3)

Now taking out the common term from the above factorisation we get H.C.F as;

= (x−1)

Therefore the H.C.F

of (x3−3x+2) and (x2−4x+3) = (x−1)