Question

find he value of p(y)=5ysq-3y+7 at y= (-1) ​

Answer 1

Answer:

$p(y) = 5ysq - 3y + 7 \\ \\ p( - 1) = 5 \times ( - 1)sq - 3 \times ( - 1) + 7 \\ \\ = - 5sq + 3 + 7 \\ \\ = 10 - 5sq$