Math, asked by studhivyashri12240, 2 months ago

find he value of p(y)=5ysq-3y+7 at y= (-1)

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Answered by Sankalp050

2

Answer:

$p(y) = 5ysq - 3y + 7 \\ \\ p( - 1) = 5 \times ( - 1)sq - 3 \times ( - 1) + 7 \\ \\ = - 5sq + 3 + 7 \\ \\ = 10 - 5sq$

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