Question

Find he value of x and y by substitution method
3x −5y −6=0
2x+3y −61=0

Answer 1

Answer:

x = 13 , y = 9

Step-by-step explanation:

3x - 5y -6 = 0

3x - 5y = 6

x-5y = 2

x = 2+5y

Put x in 2x + 3y -61 = 0

2(2+5y) + 5y = 61

4+10y + 5y = 61

4+15y = 61

15y = 57

y = 57/15

Put y in 3x - 5y -6=0

3x - 5×57/15 -6 = 0

3x - 57/3 -6 = 0

Taking 3 as LCM we get,

3x - (57-18)/3 = 0

3x - (39)/3 = 0

3x - 13 = 0

x - 13 = 0

x = 13

Now again put x in 3x - 5y - 6 = 0

Put x = 13

So, 3(13) - 5y -6 = 0

39 - 5y = 6

-5y = -45

y = 9

So , we get x = 13 and y = 9

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