Question

Find heat energy liberated when 2 A electric current is passing through a
conductor of resistance 150 for 3 hours. Also, find the amount of energy in terms
of kilowatt-hour.​

Answer 1

Given:-

• Current ,I = 2A

• Resistance ,R = 150 Ohm

• Time taken ,t = 3 hour = 3×60×60 = 10800 s

To Find:-

• Heat liberated ,H

• Amount of Energy in term of kWh.

Solution:-

Firstly we calculate the Heat liberated .

Using Formula

• H = I²Rt

where,

I is the current

R is the Resistance

t is the time taken

Substitute the value we get

→ H = 2² × 150 × 10800

→ H = 4 × 150×10800

→ H = 600×10800

→ H = 6480000

→ H = 6.48×10⁶ J

Therefore, the heat liberated is 6.48 × 10⁶ Joules.

Now, Calculating the amount of Energy in term of kWh

As we know that ,

1 kWh = 3.6 × 10⁶ J

Therefore, 6.48 × 10⁶ J = 6.48×10⁶/3.6×10⁶

= 6.48/3.6

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 1.8 kWh

Therefore, the amount of energy in term of kWh is 1.8 kWh.

Answer 2

Answer:

Find heat energy liberated when 2 A electric current is passing through a

conductor of resistance 150 for 3 hours. Also, find the amount of energy in terms

of kilowatt-hour.