find height of a wall with the help of pythagoras theorem , whose base is 3cm and hypotenus is 5cm.
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Answer:
4cm
Step-by-step explanation:
By Pythagoras THM
Let consider height of wall be AB,base be BC and slant height be AC
so AC^2=AB^2+BC^2
(5^2)=AB^2+(3^2)
25=AB^2+9
25-9=AB^2
16=AB^2
√16=√AB^2--------ROOT SQUARE GET CANCEL
AB=4
$O WE HAVE ALREADY CONSIDERED AB BE HEIGHT OF WALL, IT IS EQUAL TO 4CM
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