Question

find heroes of 2√3x2-5x+√3

Answer 1

heya..!!!!


2√3x² - 5x + √3

=> 2√3x² -3x - 2x + √3

=> √3x(2x - √3) - 1(2x - √3)

=> (√3x - 1)(2x - √3)

=> x = 1/√3

and,

x = √3/2

Answer 2

The zeros are $\frac{\sqrt{3} }{2} \ and \ \frac{1}{\sqrt{3}}$.

Step-by-step explanation:

Let f(x) = 2√3x² - 5x + √3

To find zeros of f(x).

f(x) = 0

=> 2√3x² - 5x + √3 = 0

=> 2√3x² - 2x - 3x + √3 = 0

=> 2x(√3x - 1) - √3(√3x - 1) = 0

=> (2x - √3)(√3x - 1) = 0

=> 2x - √3 = 0 and √3x - 1 = 0

=> x = $\frac{\sqrt{3} }{2}$ and x = $\frac{1}{\sqrt{3} }$

Hence, the zeros are $\frac{\sqrt{3} }{2} \ and \ \frac{1}{\sqrt{3}}$.