Find highest common factor of the 20a²b and 25 ab²
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I hope it is helpful for you
Step-by-step explanation:
First expression = x2 - 3x - 18
= x2 - 6x + 3x - 18, by splitting the middle term - 3x = - 6x + 3x
= x(x - 6) + 3(x - 6)
= (x - 6) (x + 3)
Second expression = x2 + 5x + 6
= x2 + 3x + 2x + 6, by splitting the middle term 5x = 3x + 2x
= x(x + 3) + 2(x + 3)
= (x + 3) (x + 2)
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