Find how high will it rise and how much time will it take to return to its point of projection if a body is thrown up with a velocity of 78.4ms⁻¹?
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Given :
Initial velcoity=u=78.4m/s
Let h be the maximum height the object reaches.
The velocity at maximum height v=0m/s
From third equation of motion :V²-u²=2gh
v²=2x(-9.8)xh
h=(78.4)²/2x9.8=313.6m
From first equation of motion: V=u+gt
0=78.4 -9.8t
t=78.4/9.8 sec=8 sec
Total time taken to return to the point of projection = Time of ascent +time descent=2x8=16sec
Initial velcoity=u=78.4m/s
Let h be the maximum height the object reaches.
The velocity at maximum height v=0m/s
From third equation of motion :V²-u²=2gh
v²=2x(-9.8)xh
h=(78.4)²/2x9.8=313.6m
From first equation of motion: V=u+gt
0=78.4 -9.8t
t=78.4/9.8 sec=8 sec
Total time taken to return to the point of projection = Time of ascent +time descent=2x8=16sec
einsteinkabrain:
couldn't understand from the first equation of motion.
just substitute u and g we get value of t
total time=2u/g
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