find how many 3 digit numbers which when divided by 8 leaves the remainder 2 in each case
Answers
Answered by
0
n is a 3 digited number which is divisible by 8
to leave reminder 2 it must be of the form n+2
hence it starts from 106 and ends with 994
therefore,
994=106+(n-1)8
n=112
to leave reminder 2 it must be of the form n+2
hence it starts from 106 and ends with 994
therefore,
994=106+(n-1)8
n=112
Similar questions