Math, asked by pegasustwilight, 1 day ago

Find how many bricks of 23 cm x 11 cm x 7.5 cm are required to build a wall which is 69m x 2.4m x 0.55m

Answers

Answered by Shreyanshijaiswal81
1

Dimensions of the wall

I = 23 m

H = 11 cm

W = 7.5 m

Dimensions of the brick

l = 69 cm

b = 2.4 m

H = 0.55 m

23 m, 7.5 m, 2.4 m and 0.55 m in cm by multiplying it by 100

length = 23m = (23 × 100) cm = 2300 cm

breadth = 7.5m = (7.5 × 100 ) cm = 750cm

length of the brick is 2300 cm

breadth of the brick is 75 cm

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length = 2.4 m = (2.4 × 100) cm = 240 cm

breadth = 0.55 m = (0.55 × 100) cm = 55 cm

length of the wall is 240 cm

breadth of the wall is 55cm

V = I×b×h

V = 230×11×75

V = 189750

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V = I×b×h

V = 69× 240× 55

V = 910800

No.of bricks required to construct the wall

No. of brick = \frac {Volume\: of \:wall}{Volume \:of \:one\: brick }

=\frac {910800}{189750}

= 4.8

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