find how many integers between 200 and 500 are dovisible by 8
Answers
Answered by
17
Heya user,
A∈[500/8] = [62]
B∈[200/8] = [25]
=>A∪B = [62] - [25] = 37..
Another Method is...
The 1st term is a = 208. c.d. =8 And last term = 496..
.'. No. of terms can be taken ot as: 208+(n-1)8 = 496
=> (n-1)8 = 288
=> (n-1) = 36
=> n = No. of terms = 36+1 = 37
A∈[500/8] = [62]
B∈[200/8] = [25]
=>A∪B = [62] - [25] = 37..
Another Method is...
The 1st term is a = 208. c.d. =8 And last term = 496..
.'. No. of terms can be taken ot as: 208+(n-1)8 = 496
=> (n-1)8 = 288
=> (n-1) = 36
=> n = No. of terms = 36+1 = 37
Answered by
8
First term between 200 and 500 divisible by 8 is 208, and the last term is 496
First term, a = 208
Common difference (d) = 8
an = a + (n – 1) d = 496
⇒ 208 + (n – 1) 8 = 496
⇒ (n – 1) 8 = 288
⇒ n – 1 = 36
⇒ n = 37
Hence, there are 37 integers between 200 and 500 which are divisible by 8.
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