Question

find how many numbers are there between 100 and 500 which leave a reminder 3 when divided by 5​

Answer 1

Step-by-step explanation:

let a be the first number and d is the common difference

a +( n-1) d

the first number is 103 which leaves remainder 3 when divided with 5

and last number is 498 which leaves remainder 3 when divided with 5.

the equation comes likes this

498 = 103 + ( n-1) 5

498 = 103 + 5n - 5

498 = 98 + 5n

400 = 5n

n = 80

there are 80 integers between 100 and 500 which have remainder 3 when divided with 5 .

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