Find how many numbers between 33 and 333 are divisible by 7.
Answers
Answered by
0
Answer:
a=35
d=42-35=7
an=329
formula= an=a+(n-1)d
329=35+(n-1)7
329-35=7(n-1)
294/7=n-1
42+1=n
n=43
answer is 43
hope it helps you
Answered by
0
Given:
Numbers between 33 and 333.
To Find:
The numbers divisible by 7 between 33 and 333
Solution:
To find the numbers we need to use Arithmetic Progression,
The formula for AP is :
An = A+[n-1]×d
An = last term which is divisible by 7 between 33 and 333
An = 329
A = first term which is divisible by 7 between 33 and 333
A = 35
n = numbers to be find
d = the number to be divided
d = 7
∴329 = 35 + [n-1]*7
=> 329-35=7n-7
=> 294=7n-7
=> 294+7=7n
=> 301=7n
=> n=301/7
=> n=43
∴ 43 numbers are divisible by 7 between 33 and 333
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