Question

find how many numbers comtaining 4 digit can be formed from digits 1,2,3 ,4,0 and divisible by 5 , permutation anf combination question
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Answer 1

Answer:

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Step-by-step explanation:

We know that the rule for divisibility is that the last 2 digits must be divisible by 4 as whole like 16,04,08,12 etc.

So, our last 4 digits can be 12,24,32,44,52,32 only suppose we 1st take 12 and then we have 5 choice for 1st digit of repetition is allowed and similarly 5 for 2nd.

∴25 numbers ending with, so total number 25×5=125

Hence, the answer is 125