Question

find how many three digit natural number are divisible by 5

Answer 1

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hii !!


solution:



●By AP



No. are: 100,105,110.... 905


first term(a)=100

common difference (d)=5


let the no. of terms be n then,

=>a+(n-1)d=905

=>100+(n-1)5=905

=>(n-1)5=805

=>n-1=805/5


=>n=161+1

=>n=162


hence , no. of 3 digit no. divisible by 5 are 162



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