Question

find how many three digit natural numbers are divisible by 6​

Answer 1

Hello,

Question:- find how many three digit natural numbers are divisible by 6

Topic:- Natural Numbers.

Answer:-

Actually three digit natural numbers are from 100, 101,……999.

Actually three digit natural numbers are from 100, 101,……999.Use Arithmetic Progression(A.P) to find the three digit numbers that are divisible by 6.

Actually three digit natural numbers are from 100, 101,……999.Use Arithmetic Progression(A.P) to find the three digit numbers that are divisible by 6.So, 102, 108, 114,……..996.

Actually three digit natural numbers are from 100, 101,……999.Use Arithmetic Progression(A.P) to find the three digit numbers that are divisible by 6.So, 102, 108, 114,……..996.It is like A.P. In this series a=102(First term), d=6(Difference). l= 996 (last term). n is the number of terms.

Actually three digit natural numbers are from 100, 101,……999.Use Arithmetic Progression(A.P) to find the three digit numbers that are divisible by 6.So, 102, 108, 114,……..996.It is like A.P. In this series a=102(First term), d=6(Difference). l= 996 (last term). n is the number of terms.l =a +(n-1)d

Actually three digit natural numbers are from 100, 101,……999.Use Arithmetic Progression(A.P) to find the three digit numbers that are divisible by 6.So, 102, 108, 114,……..996.It is like A.P. In this series a=102(First term), d=6(Difference). l= 996 (last term). n is the number of terms.l =a +(n-1)d996 = 102 + (n-1) 6

Actually three digit natural numbers are from 100, 101,……999.Use Arithmetic Progression(A.P) to find the three digit numbers that are divisible by 6.So, 102, 108, 114,……..996.It is like A.P. In this series a=102(First term), d=6(Difference). l= 996 (last term). n is the number of terms.l =a +(n-1)d996 = 102 + (n-1) 6894/6 = n-1

Actually three digit natural numbers are from 100, 101,……999.Use Arithmetic Progression(A.P) to find the three digit numbers that are divisible by 6.So, 102, 108, 114,……..996.It is like A.P. In this series a=102(First term), d=6(Difference). l= 996 (last term). n is the number of terms.l =a +(n-1)d996 = 102 + (n-1) 6894/6 = n-1149 + 1= n

Actually three digit natural numbers are from 100, 101,……999.Use Arithmetic Progression(A.P) to find the three digit numbers that are divisible by 6.So, 102, 108, 114,……..996.It is like A.P. In this series a=102(First term), d=6(Difference). l= 996 (last term). n is the number of terms.l =a +(n-1)d996 = 102 + (n-1) 6894/6 = n-1149 + 1= nn=150.

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So 150 three digit numbers are divisible by 6.

Answer 2

Answer:

The three digit numbers divisible by 6 are 102,108,114,.......,996

We have a=102, an  =996  

an =a+(n−1)d

⇒996=102+(n−1)6

⇒996=102+6n-6

⇒996=96+6n

⇒6n=996-96

⇒6n=900

⇒n=900/6

⇒n=150

There are 150 such numbers divisible by 6.

Step-by-step explanation:

Using the Arithmetic Progression....an=a+(n-1)d

where,    

           an=last term

            a=first term

           n= Total number of  terms

            d=common difference