Find how many triangles can be drawn through 8 points on an circle
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Let's name each of 8 points as a,b,c,d,e,f,g,h
Let's assume that a,b&c are in one straight line, so cannot form a triangle with each other.
Now, total possible Triangle that can be formed choosing any 3 points without any colinear constraint is 8C3 = 56.
Now, out of 56 possible sets of 3 points each, there is one set a-b-c that is incapable of forming a triangle. But, remaining 55 triangle are possible.
Hence, Statement 2 is sufficient and Ans is B.
Let's assume that a,b&c are in one straight line, so cannot form a triangle with each other.
Now, total possible Triangle that can be formed choosing any 3 points without any colinear constraint is 8C3 = 56.
Now, out of 56 possible sets of 3 points each, there is one set a-b-c that is incapable of forming a triangle. But, remaining 55 triangle are possible.
Hence, Statement 2 is sufficient and Ans is B.
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