find how many two digit natural number are divisible by 4
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Answer:
Lowest two digit Number divisble 4 =12
HIghest two digit number divisble=96
Putting formula
An=a+(n-1)d
An is Highest number=96
a is lowest=12
D is 4
so
96=12+(n-1)4
96-12=4n-4
84+4=4n
88=4n
n=88/4
n=22
Total number=22
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