find how many two digit natural number are divisible by 7
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There are 13 two digits natural number divisible by 7.
sakshipathak14093:
how
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a=14
d=7
tn=98
tn=a+(n-1)d
98= 14+(n-1)7
98-14=7n-7
84=7n-7
84+7=7n
91=7n
91/7=n
n=13
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d=7
tn=98
tn=a+(n-1)d
98= 14+(n-1)7
98-14=7n-7
84=7n-7
84+7=7n
91=7n
91/7=n
n=13
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hope it is helps you
plz follow me
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