Question

Find how many two digits natural numbers are divisible by 7

Answer 1

Ans: 13

step by step

First two digit number divisible by 7 =14

Second two digits number = 21

...................

Last two digit number divisible by 7 = 98

it is A.P ,Here a= 14 , d= 7

a+ (n -1) d = 98

14 + (n -1) 7 =98

(n--1) 7 =98-14

(n - 1)7 =84

(n-1) =84/7= 12

n - 1 = 12

n= 12 +1 =13

check: The numbers are 14,21,28,35,42,49,56,63,70,77,84,91,98

mark as brainliest answer

Answer 2

13 numbers.

✔️Solution -

14, 21, 28, 35,...98 are in A.P

First term, a = 14

Common difference, d = 21-14 = 7

Last term, tn = 98

tn = a + (n-1)d

98 = 14 + (n-1)7

98 = 14 + 7n - 7

7n = 98-7

7n = 91

n = 13