Find Hypotaniuous if perpendicular is (a+1) and base is (a+2)
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Step-by-step explanation:
hypotaneous² = base² + perpendicular ²
hypo² = (a+1)² + (a+2)²
hypo² = 2a² + 5 + 5a
hypo = √ 2a² + 5a + 5
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- = (a+1)^ +(a+2)^
- a^+2a+1+a^+4a+4
- 2a^+6a+5
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